Correct Answer - `u = sqrt(gL(2+(3 sqrt(3))/(2)))`
Now, we have following equations
(1) `T_(Q) = 0` Therefore, `mg sin theta = (mv^(2))/(L)` ….(1)
(2) `v^(2) =u^(2) - 2gh = u^(2) - 2gL(1 + sin theta)` …..(2)
(3) `QD = (1)/(2) ("range")` ….(3)
`u = sqrt(gL(2+(3 sqrt(3))/(2)))`.