Correct Answer - A
During the impact , some part of incident kinetic energy is temporarily stored in the form of potential energy. The potential energy will be maximum when particles compress to the maximum, at the maximum compression , both particles move with the same velocity.
`m u = (m + eta m)v rArr v = ((u)/( 1 + eta))`
`K_(i) = (1)/(2) m u^(2)`
`K.E.` at the maximum compression,
`(1)/(2) ( m + eta m) v^(2) = (1)/(2) m u^(2) ((1)/( 1 + eta))`
`(P.E.)_(max) = (1)/(2) m u^(2) - (1)/(2) m u^(2) ((1)/(1 + eta))`
`= ((eta)/( eta + 1))^(2) (1)/(2) m u^(2) = ((eta)/( eta + 1))K`
