Correct Answer - C
The velocity component along the wall remains same (due to no force along the wall and the velocity component perpendicular to the wall just reverses (due to normal force)
`Delta p_(y) = 0`
`Delta p_(x) = mv cos 60^(@) - (-mv cos 60^(@))`
`= 2mv cos 60^(@) = mv`
`F_(x) = (Delta p_(x))/(Delta t) = (mv)/(Delta t) = ( 5 xx 10^(-3) xx 20)/(2 xx 10^(-3)) = 500 N` , to the right