Correct Answer - 39
`Q_(AB) = DeltaU_(AB) +W_(AB)`
`W_(AB) = 0`
`DeltaU_(AB) = (f)/(2) nR DeltaT`
`rArr (f)/(2) (DeltaPV)`
`DeltaU_(AB) = (5)/(2) (DeltaPV)`
`Q_(AB) = 2.5 P_(0)V_(0)`
Process `BC BC`
`Q_(BC) = DeltaU_(BC) +W_(BC)`
`Q_(BC) = 0 +2P_(0)V_(0)ln2 = 1.4 P_(0)V_(0)`
`Q_("net") = Q_(AB) +Q_(BC) =3.9 P_(0)V_(0)`