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Helium gas goes through a cycle ABCDA (consisting of two isochoric and isobaric lines) as shown in figure Efficiency of this cycle is nearly: (Assume the gas to be close to ideal gas)
image
A. `15.4%`
B. `9.1%`
C. `10.5%`
D. `12.5%`

1 Answer

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Best answer
Correct Answer - A
`eta = (p_(0)v_(0))/((f)/(2)(p_(0)v_(0))+(f)/(2)(2p_(0))v_(0)+2p_(0)v_(0)) = (1)/((3)/(2)+3+2) = (200)/(13) = 15.4%`

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