Question

If percentage change in length is `1%` with change in temperature of a cuboid object `(l xx 2l xx3l)` then what is precentage change in its area and volume.

Answer 1

percentage change in length will change in temperature `= % l`
`(Deltal)/(l) xx 100 = alpha Delta theta xx 100 = 1`
change in area
`rArr %A = (DeltaA)/(A) xx 100 = beta Delta theta rArr 2 (alpha Delta theta xx 100)`
`% A = 2%`
change in volume
`% V = (DeltaV)/(V) xx 100 = V Delta theta xx 100 = 3 (alpha Delta theta xx 100)`
`% V = 3%`.