Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
197 views
in Physics by (86.6k points)
closed by
In the previous problem, the distance between the balls when their velocity vectors are perpendicular is
A. `(2(v_+ v_(2))sqrt(v_(1)v_(2)))/(g)`
B. `(v_(1) + v_(2)sqrt(v_(1)v_(2)))/(g)`
C. `(v_(1) + v_(2)sqrt(v_(1)v_(2)))/(g)`
D. `(v_(1) + v_(2)sqrt(v_(1)v_(2)))/(2 g)`

1 Answer

0 votes
by (86.0k points)
selected by
 
Best answer
Correct Answer - C
`x_(1) = v_(1) t, x_(2) = v_(2) t`
Distance between balls `d = (v_(1) + v_(2))t`
`= ((v_(1) + v_(2))sqrt(v_(1)v_(2)))/(g)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...