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A body is projected with a speed (u) at an angle to the horizontal to have maximum range. What is its velocity at the highest point ?

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A body is projected with a speed (u) at an angle to the horizontal to have maximum range. What is its velocity at the highest point ?
A. zero
B. `u sqrt(2)`
C. `u`
D. `(u)/(sqrt(2))`
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Correct Answer - D
For maximum range, `theta=45^(@)`
At the highest point, `v=ucos theta=(u)/(sqrt(2))`
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