Correct Answer - B
Here range `=2h tan alpha=(u^(2)sin 2theta)/g` and `h=(u^(2)sin^(2) theta)/2g` Dividing `2tan alpha=(2sin 2theta)/sin^(2)theta rArr tan alpha=2cot theta`
`:.u^(2)(2gh)/(sin^(2)theta)=(2gh)/(((2cotalpha)/sqrt(1+4cot^(2)alpha)))=(2gh(1+4cot^(2)alpha))/(4 cot^(2)alpha)=gh(1/2tan^(2)alpha+2)`
`tan theta=2cot alpha`