Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
182 views
in Physics by (76.7k points)
closed by
A uniform thin rod is bent in the form of closed loop `ABCDEFA` as shown in the figure. The `y-` coordinate of the centre of mass of the system is
image
A. `(2r)/(pi)`
B. `-(6r)/(3pi+2)`
C. `-(2r)/(pi)`
D. Zero

1 Answer

0 votes
by (76.5k points)
selected by
 
Best answer
Correct Answer - B
The centre of mass of semicircular ring is at a distance `(2r)/(pir) ` from its centre. `(` Let `lambda=` mass `//` length `)`
`:. Y_(cm)=(lambdapirxx(2r)/(pi)-lambda xx 2pirxx(4r)/(pi))/(lambda pir+lambdar+lambdar+lambda xx 2pir)=-(6r)/(3pi+2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...