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A projectile is thrown at angle `beta` with vertical.It reaches a maximum height `H`.The time taken to reach the hightest point of its path is

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A projectile is thrown at angle `beta` with vertical.It reaches a maximum height `H`.The time taken to reach the hightest point of its path is
A. `sqrt(H/g)`
B. `sqrt((2H)/g)`
C. `sqrt(H/(2g))`
D. `sqrt((2H)/(g cos theta))`
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1 Answer

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Correct Answer - B
`t=sqrt((2H)/g)`
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