It is a one dimensional motion. So, let us choose the east direction as positive and the west as negative. Now given that
`v_(S)` = velocity of Seeta `= 1ms^(-1)`
and `v_(G)` = velocity of Geeta `= -2 ms^(-1)`
Thus, `v_(SG)` = velocity of Seeta with respect to Geeta
`=v_(S)-v_(G)=1-(-2)=3 ms^(-1)`
Hence, velocity of Seeta with respect to Geeta is 3 m/s due east.