Question

A block of mass 5 kg is placed on a rough inclined plane. The inclination of the plane is gradually increased till the block just begins to slide down. The inclination of the plane is than 3 in 5. The coefficient of friction between the block and the plane is (Take, `g = 10m//s^(2)`)
A. `(3)/(5)`
B. `(3)/(4)`
C. `(4)/(5)`
D. `(2)/(3)`

Answer 1

Correct Answer - B
`sin theta=(3)/(5)`

`mu = tan theta implies mu = (3)/(4)`