Question

What is the second lowest frequency for standing waves on a wire that is 10.0 m long has a mass of 100 g and is stretched under a tension of 25 N which is fixed at both ends ?
A. 2.5 Hz
B. 5.0 Hz
C. 7.5 Hz
D. 10.0 HZ

Answer 1

Correct Answer - B
`v=sqrt(T/(mu))=sqrt(25)/((100xx10^(-3))/(10))=50 `
`:. v_(0)=v/(2L)=50/(2xx10)=2.5 Hz`
`:. v_(1)=2v_(0)=5Hz`
`v_(2)=3v_(0)=7.5 Hz`