Correct Answer - D
Let height of tower is h and body takes t time to reach to ground when it fall freely.
`therefore h = (1)/(2) g t^(2)` ….(i)
In last second i.e., t th second body travels `= 0.36 h`
It means in rest of the time i.e., in (t - 1) second it travels
`=h-0.36h=0.64h`
Now applying equation of motion for (t - 1) second
`0.64h=(1)/(2)g(t-1)^(2)`
From Eqs. (i) and (ii) we get, t = 5 s and h = 125 m
