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A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)C` .How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 2400 J kg ^(-1)K^(-1)` and the specific latent heat of ice `= 3.4 xx 10^(3)J kg^(-1)`
A. 20 g
B. 30 g
C. 40 g
D. 50 g

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Correct Answer - D
Heat required to melt ice `=100xx80=8000cal`
Maximum heat than can be given by water `=200xx1xx(20-0)=4000cal`
Whole ice is not melted, hence, equilibrium temperature `=0^@C`
Amount of ice melted `=(4000)/(80)=50g`

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