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Two uniform circular discs, each of mass `1kg` and radius `20cm`, are kept in contant about the tangent passing through the point of contact. Find the moment of inertia of the system about the tangent passing through the point of contact.

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`Mass M=1 kg, r=20xx10^(-2) m`
`I_(1)=(MR^(2))/4+MR^(2)=(5MR^(2))/4`
Similarly, `I_(2)=(5MR^(2))/4,I=I_(1)+I_(2)`
`:. I=(10MR^(2))/4=(10xx1xx(20xx10^(-2))^(2))/4=0.1 kgm^(2)`

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