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A uniform rod `AB` of mass `m` length `2a` is allowed to fall under gravity with `AB` in horizontal. When the speed of the rod is `v` suddenly the end `A` is fixed. Find the angular velocity with which it begins to rotate.

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`bar(L)_(1)=bar(L)_(2)rArrmva=Iomega`
`mva=(m(2a)^(2))/3 omegarArromega=(3v)/(4a)`

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