Correct Answer - D
`omega=0,t=2s,`
`theta=50(2pi)=100 pi rad`
`:. alpha==(2 theta)/(t^(2))=(200 pi)/4=50 pi rads^(-2)`
`theta` in `4 sec, theta=1/2alphat^(2)=1/2(50 pi)(16)`
`=400 pi rad`
in the last `2 sec theta=400 pi-100 pi=300 pi rad`
`:.` no. of rotation =`(theta)/(2pi)=(300 pi)/(2pi)=150`