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The angular frequency of a fan of moment of inertia `0.1kgm^2` is increased from 30rpm to 60rpm when a torque of `0.03Nm` acts on it. The number of revolutions made by the fan while the angular frequency is increased from 30rpm to 60rpm
A. `7.855 rev`
B. `6.855 rev`
C. `5.855 rev`
D. `8.855 rev`

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Best answer
Correct Answer - A
`tau=Ialpha,omega^(2)-omega_(0)^(2)=2alphatheta,theta=2piN`

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