Question

A parallel plate air capacitor is charged to a potential difference of `V` volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an isulating handle. As a result the potential difference between the plates
A. decreases
B. does not change
C. becomes zero
D. increases

Answer 1

Correct Answer - D
`C=(epsilonA)/d` if d increases then C decreases
q=CV here q is constant so V increases