Correct Answer - B
From force diagram, `T = 3a`......(i),
`T_(1) - T = 3a`........(ii) `3g - T_(1) = 3a`.......(iii)
After solving eqs. (i),(ii)
`:.` Stress `= (T)/(A) = (10)/(0.005xx10^(-4))`
`therefore` The elastic energy stored per unit volume
`= (1)/(2) xx "stress" xx "strain"`
`= (1)/(2) xx "stress" xx ("stress")/(Y) (because Y = ("Stress")/("Strain"))`
`= (Stress"^(2))/(2Y) = (((10)/(0.05xx10^(-4)))^(2))/(2xx2xx10^(11)), = 1000J//m^(3)`