Correct Answer - D
The bar is at equilibrium. The net force form right or left of a section of `BC` is `70KN`. We know that the extension due to external forces `F` is given
`Delta l = (Fl)/(Ay), Delta_(BC) = ((70xx10^(3))xx1)/(1xx2xx10^(11)) = 3.5xx10^(-7)m`