Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
160 views
in Physics by (86.6k points)
closed by
A recantangular frame is to be suspended symmetrically by two strings of equal length on two supports (figure).It can be done in one of the following three ways:
image
A. the same in all cases
B. least in (a)
C. least in (b)
D. least in (c )

1 Answer

0 votes
by (86.0k points)
selected by
 
Best answer
Correct Answer - C
Consider the FBD diagram of the rectangular frame
image
Balancing vertical forces `2T sin theta - mg = 0" [T is tension in the string]"`
`implies " "2T sin theta = mg " .....(i)"`
Total horizontal force = `T cos theta - T cos theta = 0`
Now from Eq. (i), `T = (mg)/(2 sin theta)`
As mg is constant
`implies " "T prop (1)/(sin theta) implies T _("max")=(mg)/(2 sin theta_(min))`
`" "sin theta_("min")=0 implies theta_("min")=0`
No option matches with `theta = 0^(@)`
`T_("min")=(mg)/(2sin theta_("max"))" "("Since, "sintheta_("max")=1)`
`sin theta_("max")=1implies theta=90^(@)`
Matches with option (b)
Hence, tension is least for the case (b).
Note We should be careful when measuring the angle, it must be in the direction as given in the diagram.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...