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For a common emiter configuration if `a` and `beta` have their usualy meaning , the incorrrect relationship between `a and beta` is :
A. `alpha=(beta^(1))/(1+beta^(2))`
B. `(1)/(alpha)=(1)/(beta)+1`
C. `alpha=(beta)/(1+beta)`
D. `alpha=(beta)/(1+beta)`

1 Answer

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Best answer
Correct Answer - A::C
`alpha=(I_(C))/(I_(e)),beta=(I_(C))/(I_(b))`
`I_(e)=I_(b)+I_(c)rArr(I_(e))/(I_(e))=(I_(b))/(I_(c))+1rArr(I)/(alpha)=(I)/(beta)+1`
`alpha = (beta)/(1+beta)`

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