Correct Answer - B
From the figure
`AC_(1)=AC_(2) =C_(1)C_(2)`=radius
`:. angle AC_(1)B=120^(@)`
Hence the resistance of four sections are shown in the figure
Hence equivalent resistance R across AB is
`1/R=1/24+1/12+1/12` or `R=4 Omega`
`:. ` Power =`(V^(2))/R=((20)^(2))/4=100 ` watt.