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In the question number 62. the maximum height attained by the ball is
A. 11.25 m
B. 48.2 m
C. 23. 5 m
D. 68 m

1 Answer

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Best answer
Correct Answer - A
The maximum height is given by
`H=(u^(2)sin^(2)theta)/(2g)=((30)^(2)sin^(2)30^(@))/(2xx10)=11.25m`

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