Correct Answer - C
From `(1)/(f)=(1)/(v)-(1)/(u)=(1)/(10)-(1)/(-10)=(1)/(5)rArr f=5cm`
From graph `Delta u = 0.1 cm, Delta v = 0.1 cm`
But `(Deltaf)/(f^(2))=(Deltav)/(v^(2))+(Deltau)/(u^(2))`
so `Deltaf=((0.1)/(100)+(0.1)/(100))(25)=0.05`
`rArrf = (5 pm 0.05)cm`