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A block of mass `2kg` is propped from a heught of `40cm` on a spring where force constant is `1960Nm^(-1)` The maximum distance thought which the spring compressed by
A. 5 cm
B. 15 cm
C. 20 cm
D. 10 cm

1 Answer

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Best answer
Correct Answer - D
`mg(h+x)=1/2kx^2`
Here, m= 2 kg, h=40 cm
`k=1960 N m^(-1) and g=10 m s^(-2)`
`therefore 2 xx 10 (0.40+x)=1/2xx1960 x^2`
On solving , we get x = 10 cm

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