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Figure shows a uniformly charged hemisphere of radius R. It has a volume charge density `rho`. If the electric field at a point 2R, above the its center is E, then what is the electric field at the point 2R below its center?
image
A. `(rhoR)/(6epsilon_(0))+E`
B. `(rhoR)/(12 epsilon_(0))-E`
C. `(-rhoR)/(6epsilon_(0))+E`
D. `(rhoR)/(24 epsilon_(0))+E`

1 Answer

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Best answer
Correct Answer - B
image
Apply principle of superposition
Electric field due to a uniformly charged sphere`=(rho R)/(12 epsilon_(0)), E_("resultant")=(rho R)/(12 in_(0))-E`

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