Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
171 views
in Physics by (41.6k points)
closed by
From the dimensional consideration, which of the following equation is correct
A. `T=2pisqrt(R^(3)/(GM)`
B. `T=2pisqrt((GM)/(R^(3))`
C. `T=2pisqrt((GM)/(R^(2))`
D. `T=2pisqrt((R^(2))/(GM)`

1 Answer

0 votes
by (57.3k points)
selected by
 
Best answer
Correct Answer - A
Taking, `T=2pisqrt((R^(3))/(GM)`
Substituting the dimensions, LHS = [T]
RHS `2pi|sqrt((R^(3))/(GM))|=sqrt((["L"]^(3))/(["M"^(-1)"L"^(3)"T"^(-2)]["M"]))=sqrt(["T"]^(2))=["T"]`
Thus, LHS=RHS for `T=2pisqrt((R ^(3))/(GM))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...