Question

A linear harmonic oscillator of force constant `2 xx 10^(6)N//m` and amplitude `0.01 m` has a total mechanical energy of `160 J`. Its
A. maximum potential energy is 160 J
B. maximum potential energy is 100 J
C. minimum potential energy is zero
D. minimum potential energy is 100 J

Answer 1

Correct Answer - A
(a)`(1)/(2)kA^(2)=(1)/(2)xx2xx10^(6)xx(0.01)^(2)=100 J`
At mean position ,
U=60 J and K=100 J
At extreme positions ,
U=160 J and K=0