Question

A mass of 0.2 hg is attached to the lower end of a massles spring of force constant `200(N)/(m)` the opper end of which is fixed to a rigid support. Study the following statements.
A. In equilibrium , the spring will be stretched by 1 cm
B. If the mass is raised till the spring becomes unstretched and then released , it will go down by 2 cm before moving upwards
C. The frequency of oscillation will be nearly 5 Hz
D. All of the above

Answer 1

Correct Answer - D
(d) At equilibrium , `x=(mg)/(k)=(0.2xx10)/(200)=0.01 m = 1cm `
`f=(1)/(2pi)sqrt((K)/(m)) =(1)/(2pi)sqrt((200)/(0.2))~~ 5 Hz`