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The variation of potential energy of harmonic oscillator is as shown in figure. The spring constant is
image
A. `1 xx 10^(2)Nm^(-1)`
B. `1.5 xx 10^(2) Nm^(-1)`
C. `2 xx 10^(2)Nm^(-1)`
D. `3 xx 10^(2)Nm^(-1)`

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Correct Answer - B
(b) `(1)/(2) kA^(2)=(0.04-0.01)J=0.03 J`
`therefore k=(0.06)/(A^(2))=(0.06)/((0.02)^(2))=150 Nm^(-1)`

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