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Two pendulums having time period `T` and `(5T)/(4)`. They start`S.H.M.` at the same time from mean position. what will be the phase difference between them after the bigger pendulum has completes one oscillation ?
A. `45^(@)`
B. `90^(@)`
C. `60^(@)`
D. `30^(@)`

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Correct Answer - B
(b) When bigger pendulum of time period (5T/4) complete one vibration , the smaller pendulum will complete (5/4) virations . It means the smaller pendulum will be leading, the bigger pendulum by phase T/4 s`=pi//2 "rad"=90^(@)`.

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