Question

Assume that one early morning when the temperature is `10^(@)C` a driver of an automobile gets his gasoline tank which is made of steel, filled with `75` L of gasoline, which is also at `10^(@)C` Durign the day, the temperature rises at `30^(@)C` how much gasoline will overflow ?
(Given, `alpha` for steel = `1.2 xx 10^(-5)"^(@) C^(-1),gamma` for gasoline `= 9.5 xx 10^(-4)"^(@)C)`

Answer 1

Change in volume of gasoline ,`DeltaV (g)= gamma_(g)VDeltaT =9.5xx10^(-4)xxVxx20=190xx10^(-4)V`
Change in volume of steel tanks, `DeltaV_(s)=gamma_(s)VDeltaT=3alpha_(s)-DeltaV=3xx1.2xx10^(-5)xxVxx20=7.2xx10^(-4)V`
`therefore` Volume of gasoline theat overflows
`=DeltaV_(g)-DeltaV_(s)=(190xx10^(-4)-7.2xx10^(-4))V=182.8xx10^(-4)xx75=1.37L.`