Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
860 views
in Physics by (41.5k points)
closed by
The ratio of rms speed of an ideal gas molecules at pressure p to that at pressure 2p is
A. `1:2`
B. `2:1`
C. `1: sqrt2`
D. `sqrt2 :1`

1 Answer

0 votes
by (57.3k points)
selected by
 
Best answer
Correct Answer - C
According to the question In the first condition,
`p=1/3pC_(rms)^(2)`
In the second condition,
`2p=1/3pC_(rms)^(2)`
Dividing Eq. (i) by Eq. (ii), we get
`(C_(rms)^(2))/(C_(rms)^(2))=1/2rArr(C_(rms))/(C_(rms))=1/sqrt2`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...