Question

How many degrees of freedom have the gas molecules, if under standard conditions the gas density is `1.3 kg m^(-3)` and the velocity of sound propagation in it is `C=330 m s^(-1)`.
A. 5
B. 6
C. 7
D. 8

Answer 1

Correct Answer - A
We know that, `v=sqrt((gammap)/(p))`
`gamma=(v^(2)p)/(p)=((330)^(2)xx1.3)/(1.015xx10^(5))=1.4`
`rArr" "1+1/n=1.4rArrn=5`