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Given `vecF=(4hati-10hatj)and vecr=(5hati-3hatj)`. then torque `vectau` is

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Here `vecr= 5hati -3hatj +0hatk and vecF= 4hati-10hatj+0hatk`
`therefore vectau = vecrxx vecF= |{:(hati,,hatj,,hatk),(5,,-3,,0),(4,,-10,,0):}| = hati(0-0)- hatj (0-0) +hatk(-50+12)= -38hatk`

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