Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
372 views
in Physics by (41.5k points)
closed by
Obtain the different coefficient of the following :
(i) `(x-1)(2x+5)`
(ii) `(1)/(2x+1)`
(iii) `(3x+4)/(4x+5)`
(iv) `(x^(2))/(x^(3)+1)`

1 Answer

0 votes
by (57.3k points)
selected by
 
Best answer
Correct Answer - (i) `4x + 3`
(ii) `- (2)/((2x+1)^(2))`
(iii) `-(1)/((4x+5)^(2))`
(iv) `(2x-x^(4))/((x^(3)+ 1)^(2))`
(i) `(d)/(dx) (x-1)(2x+5)`
`" "=(x-1)(d)/(dx) (2x+ 5) + (2x+ 5) (d)/(dx) (x-1)`
`= (x-1)(2) + (2x+5) (1) = 2x -2+2x+5`
`" "=4x + 3`
(ii) `(d)/(dx) (1)/((2x+1))= (0-2)/((2x+1)^(2))= (-2)/((2x+1)^(2))`
(iii) `(d)/(dx) ((3x+4)/(4x+5)) = ((4x+5)(3)- (3x+4)(4))/((4x+5)^(2))`
`= (-1)/((4x+5)^(2))`
(iv) `(d)/(dx) ((x^(2))/(x^(3)+1)) = ((x^(3)+1)(2x)-x^(2)(3x^(2)))/((x^(3)+1)^(2))`
`= (2x^(4) + 2x -3x^(4))/((x^(3)+ 1)^(2)) = (2x- x^(4))/((x^(3)+ 1)^(2))`

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...