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The angles between the two vectors `vecA=3hati+4hatj+5hatk` and `vecB=3hati+4hatj-5hatk` will be
A. zero
B. `180^(@)`
C. `90^(@)`
D. `45^(@)`

1 Answer

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Best answer
Correct Answer - 3
`cos theta = (vecA*vecB)/(AB) = ((3hati+4hatj+5hatk)*(3hati+4hatj-5hatk))/((5sqrt2)(5sqrt2))=0`
`rArr theta = 90^(@)`

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