Question

For a body, angular velocity `vecomega= hati-2hatj+3hatk` and radius vector `vecr=hati+hatj+hatk`, then its velocity `(vecv= vecomega xx vecr)` is :
A. `-5hati + 2hatj+3hatk`
B. `-5hati+2hatj-3hatk`
C. `-5hati-2hatj +3hatk`
D. `-5hati-2hatj-3hatk`

Answer 1

Correct Answer - 1
`vecv= vecomegaxx vecr`
`vec v= |{:(hati,,hatj,,hatk),(1,,-2,,3),(1,,1,,1):}|=hati(-2-3)- hatj(1-3)+hatk(1+2)`
`= -5hati+2hatj+3hatk`