Question

A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall the angle of projection of ball is :-
A. `tan ^(-1)((3)/(2))`
B. `tan^(-1)((2)/(3))`
C. `tan ^(-1)((1)/(2))`
D. `tan^(-1)((3)/(4))`

Answer 1

From equation of trajectory. `y= x tan theta [ 1-(x)/(R ) ] rArr 3 = 6 tan theta [ 1- (1)/(4)] rArr tan theta = (2)/(3) `