The force acting on the plate are
`(i)` Buoyancive force of water acting upward
`B = rho_(1)V_(Sub) g = 1 xx (1.54 xx 10 xx 0.2)/(2) xx 980 = 1509.2 "dyne"`.
`(ii)` Weight of the system acting downward
`= (8.2) xx 980 "dyne"`
`(iii)` Force of surface tension acting downward
`= 2 (l xx b)T = 2(10 + 0.2) 73 = 1489.2`
So net downward force `= mg +` (surface tension force) `- B = (8.2) xx 980 + 1489.2 - 1509.2 = 8016.008 "dyne" = 8.1786 gm` force
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/1609678517115263798szpvbLEmtX95VEl2.png)