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A rectagular wire frame with one movable side is convered by a soap film (fig.). What work `(erg)` will be done if this side of the frame is moved a distance `S = 2 mm` ? The length of the movable side is `l = 6cm`. The surface tension of the soap film is `alpha = 40 "dyne"//"cm"`.

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Correct Answer - `96`
`F = 2Tl = 2 xx 40 xx 6 = 480 "dyne"`
`W = F xx = 480 xx 0.2 = 96 erg`

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