Question

From a circle of radius a, an isosceles right angles triangle with the hypotenuse as the diameter of the circle is removed. The distance of the centre of mass of the remaining portion from the centre of the circle is
A. `3(pi-1)a`
B. `((pi-1)a)/(6)`
C. `(a)/(3(pi-1))`
D. `(a)/(3(pi+1))`

Answer 1

Correct Answer - C

`=((sigmapiR^(2))(0)-sigma{(1)/(2)(2R)(R)}{-(R)/(3)})/(sigmapiR^(2)-sigmaR^(2))=(R)/(3(pi-1))`