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The charge flowing through a conducting wire with time t is given by the formula `q=2t^(2)+3t+1` (coulombs). Find the current `i=dq//dt` at the end of the `5^(th)` second.

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Correct Answer - `23` ampere
`i=(dq)/(st)=4t+3`
`((dq)/(dt))_(" at" t=5 sec)=4(5)+3=23 "Ampere"`.

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