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in Physics by (90.2k points)
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A force `F=ahati+bhatj+chatk` is acted upon a body of mass `m`. If the body starts from rest and was at athe origin initially, find its new coordinate after time `t`.
A. `(at^(2))/(2m),(bt^(2))/(2m),(ct^(2))/(2m)`
B. `(at^(2))/(2m),(2bt^(2))/m,(ct^(2))/(2m)`
C. `(at^(2))/m,(bt^(2))/m,(ct^(2))/(2m)`
D. none of these

1 Answer

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Best answer
(a) `F=mAimpliesA=1/m(ahati+bhatj+chatk)`
Distancre travelled,
`S=ut+1/2At^(2)`
`s=0xxt+1/2 1/m (ahati+bhatj+chatk)t^(2)`
`s=(ahati+bhatj+chatk)(t^(2))/(2m)`

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