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A force `F=(2hati+3hatj-hatk)N` is acting on a body at a position `r=(6hati-3hatj-2hatk)`. Calculate the torque about the origin
A. `(3hati+2hatj+12hatk)Nm`
B. `(9hati+2hatj+7hatk)Nm`
C. `(hati+2hatj+12hatk)Nm`
D. `(3hati+12hatj+hatk)Nm`

1 Answer

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(a) `tau=rxxF=|(hati, hatj, hatk),(6,3,-2),(2,3,-1)|`
`=hati(-3+6)-hatj(-6+4)_hatk(18-6)`
`=tau=(3hati+2hatj+12hatk)Nm`

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