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A particle is projected at an angle `60^(@)` with the horizontal with a speed `10m//s`. Then, latus rectum is (Take `g=10m//s^(2)`)
image
A. `5m`
B. `15m`
C. `10m`
D. `0`

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Best answer
(a) From review of concepts of the chapter
Latusrectum `=(2a^(2)cos^(2)alpha)/g=(2xx10^(2)xxcos^(2)60^(@))/10=5m`

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